Q & A – Fluid Mechanics – Fluid Properties – Q.2

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Q & A – Fluid Mechanics – Fluid Properties – Q.2

Q & A – Fluid Mechanics – Fluid Properties – Q.2

Question No.2

Calculate the capillary rise in mm in a glass tube of 6 mm diameter when immersed in (a) water, and (b) mercury, both liquids being at 20oC. Assume σ to be 73 × 10−3 N/m  for water and 0.5 N/m for mercury. The contact angle for water and mercury are zero and 130o respectively.

Given :

  • Glass tube of diameter D = 6 mm
  • σw=7310N/m
  • θw=0o
  • σHg=0.5  N/m
  • θHg=130o

Solution :

When the glass tube is immersed in water :

Hw=4σwcosθwγwD

Hw=473103cos0o98100.0061000=4.96mm

When the glass tube is immersed in mercury :

HHg=4σHgcosθHgγHgD HHg=40.5cos130o981013.60.0061000=1.61mm

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